1,2,3,4,5 and 6 are the possible outcomes when the die is thrown.
Lets assume die of red colour be R, die of white colour be W, die of blue colour be B.
So, the total number of elements in the sample space =6×3=18
The sample space of the event is
S={(R,1),(R,2),(R,3),(R,4),(R,5),(R,6),(W,1),(W,2)(W,3),(W,4),(W,5),(W,6),(B,1),(B,2),(B,3),(B,4),(B,5),(B,6)}