One end of a 2.35m long and 2.0cm radius aluminium rod (K=235W.m−1K−1) is held at 20∘C. The other end of the rod is in contact with a block of ice at its melting point. The rate in kg.s−1 at which ice melts is :
(Latent heat of fusion = 336×103J/kg)
A
48π×10−6
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B
24π×10−6
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C
2.4π×10−6
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D
4.8π×10−6
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Solution
The correct option is C2.4π×10−6 Rate of heat transfer is Q/t=K×(πr2)×ΔT/L=235×π×4×10−4×(20−0)/2.35=0.8πJs−1
Latent heat of fusion is 336×103J/kg
So rate of melting of ice is 0.8π/336×103kg.s−1=2.38π×10−6kg.s−1