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Question
One end of a cylindrical glass rod ends in a hemispherical surface of radius R = 20 mm.
- Find the image distance of a point object on the axis of the rod, 80 mm to the left of the vertex. The rod is in air.
One end of a cylindrical glass rod ends in a hemispherical surface of radius R = 20 mm.
- Find the image distance of a point object on the axis of the rod, 80 mm to the left of the vertex. The rod is in air.
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Solution
The correct option is A 120 mm
μ1=1,μ2=1.5,R=+20 mm,u=−80 mm
1.5v−1−80=1.5−120
v′=+120 mm
The image is therefore formed at the right of the vertex (v is positive) and at distance of 120 mm from it.
120 mm
μ1=1,μ2=1.5,R=+20 mm,u=−80 mm
1.5v−1−80=1.5−120
v′=+120 mm
The image is therefore formed at the right of the vertex (v is positive) and at distance of 120 mm from it.
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