One end of a uniform wire of length $L$ and of weight $W$ is attached rigidly to a point in the roof and a weight $W_{1}$ is suspended from its lower end. If $S$ is the area of cross-section of the wire, the stress in the wire at a height $\frac{3 L}{4}$ from its lower end is

$\frac{W_{1}}{S}$

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$\frac{W_{1} + \frac{W}{4}}{S}$

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$\frac{W_{1} + \frac{3 W}{4}}{S}$

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$\frac{W_{1} + W}{S}$

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Solution

The correct option is C
$\frac{W_{1} + \frac{3 W}{4}}{S}$

The weight hanging below the point at a distance $\frac{3 L}{4}$ from the lower end is $(W_{1} + \frac{3 W}{4})$ .

Therefore,

$S t r e s s = \frac{W_{1} + \frac{3 W}{4}}{S}$

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Q. One end of a uniform wire of length L and of weight W is attached rigidly to a point in the roof and a weight W1 is suspended from its lower end. of S is true area of cross section of the wire, the stress in the wire at a height (3L/4) from its lower end is:

One end of a uniform wire of length L and of weight W is attached rigidly to a point in the ceiling and a weight $W_{1}$ is suspended from its lower end. If S is the area of cross – section of the wire, the stress in the wire at a height 3L/4 from its lower end is

Q. One end of a uniform wire of length

L

and of weight

W

is attached rigidly to a point in the roof and a weight

W_{1}

is suspended from its lower end. If

S

is the area of cross section of the wire, the stress in the wire at a height

3 L / 5

from its lower end is

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One end of a uniform wire of length L and of weight W is attached rigidly to a point in the roof and a weight W1 is suspended from its lower end. If S is the area of cross-section of the wire, the stress in the wire at a height 3L4 from its lower end is

The correct option is C W1+3W4S The weight hanging below the point at a distance 3L4 from the lower end is (W1+3W4). Therefore, Stress=W1+3W4S

One end of a uniform wire of length $L$ and of weight $W$ is attached rigidly to a point in the roof and a weight $W_{1}$ is suspended from its lower end. If $S$ is the area of cross-section of the wire, the stress in the wire at a height $\frac{3 L}{4}$ from its lower end is

The correct option is C
$\frac{W_{1} + \frac{3 W}{4}}{S}$

The weight hanging below the point at a distance $\frac{3 L}{4}$ from the lower end is $(W_{1} + \frac{3 W}{4})$ .

Therefore,

$S t r e s s = \frac{W_{1} + \frac{3 W}{4}}{S}$