One end of steel wire is fixed to the selling of an elevator moving up with an acceleration 2m/s2 and load of 10 kg hangs from other ends area of cross section of the wire is 2 cm2. The longitudinal strain in the wire is :
A
4×1011
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2×10−6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8×10−6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3×10−6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D3×10−6 Acceleration of steel wire =2m/s2 Load mass = l0kg Area of aross section =2cm2=2×10−4m2
F⋅B⋅D––––––––––of load
T−mg=maT=m(g+a)T=12mN
Youngs modulus of steel wire =2×1011Nm−2elongation △l=FRAYΔl=(12×(10))×l(2×10−4)(2×1011)=3×10−6