One equation of a pair of dependent linear equations is $- 5 x + 7 y = 2,$ the second
equation can be :

- 10 x + 14 y + 4 = 0

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- 10 x - 14 y + 4 = 0

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10 x + 14 y + 4 = 0

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10 x - 14 y = - 4

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Solution

The correct option is A $10 x - 14 y = - 4$
$10 x - 14 y = - 4$
For a pair of dependent linear equations, the both equations must satisfies the condition-
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$
Since the equation $10 x - 14 y = - 4$ satisfies the above condition, hence the second equation is $10 x - 14 y = - 4$ .

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Similar questions

Question 9
One equation of a pair of dependent linear equations is - 5x + 7y – 2 = 0
(A) 10x + 14y + 4 = 0
(B) –10x – 14y + 4 = 0
(C) –10x + 14y + 4 = 0
(D) 10x – 14y = –4

Q. Do the equations 5x+7y=8 and 10x+14y=4 represent a pair of concident lines ? Justify your answer.

Q. For the pair of linear equations

5 x + 7 y = 12

and

10 x + 14 y = 20

the solution set is____

Q. The equation of the circle touching the

y -

axis whose radius is

5

units and

y -

coordinate of the centre is

- 7,

Q. One equation of a pair of dependent equations is −5x + 2y = 4. The second equation can be

(a)

10 x + 4 y + 8 = 0

(b)

- 10 x - 4 y + 8 = 0

(c)

- 10 x + 4 y = 8

(d)

10 x - 4 y = 8

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One equation of a pair of dependent linear equations is −5x+7y=2, the secondequation can be :

The correct option is A 10x−14y=−410x−14y=−4For a pair of dependent linear equations, the both equations must satisfies the condition-a1a2=b1b2=c1c2Since the equation 10x−14y=−4 satisfies the above condition, hence the second equation is 10x−14y=−4.

One equation of a pair of dependent linear equations is $- 5 x + 7 y = 2,$ the second
equation can be :