Question

One Faraday of current was passed through the electrolytic cell placed in series containing solution of Ag${}^{+}$, Ni${}^{+}$, Cr${}^{+}$. the amount of Ag (at.wt.=108), Ni (at.wt.=59) and Cr (at.wt.=52) deposited will be :

• A. Ag - 108 g ,Ni - 29.5 g Cr - 17.3 g
• B. Ag - 108 g, Ni - 9.0 g, Cr - 52.0 g
• C. Ag - 108 g, Ni - 108.0 g, Cr - 108.0 g
• D. Ag - 108 g, Ni - 117.5 g, Cr - 166.0 g

Answer 1

Answer: (A)

Ag - 108 g ,Ni - 29.5 g Cr - 17.3 g

The equivalent weights of Ag, Ni and Cr are 108, 29.5 and 17.3 respectively.
One faraday of electrcity will deposit one equivalent of an element.
Hence, when one faraday of current was passed through the electrolytic cell placed in series containing solution of ${Ag}^{+}$, ${Ni}^{2+}$ and ${Cr}^{3+}$, the amount of silver, nickel and chromium deposited will be 108 g, 29.5 g and 17.3 g respectively.