One – fifth of a number is equal to ${\frac{5}{8}}^{t h}$ of another number. If 35 is added to the first number, the result is four times the second number. The second number is:

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125

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Solution

The correct option is B
40

Let the number be x and y. Then,

$\frac{x}{5}$ = $\frac{5 y}{8}$

$⟹$ y = $\frac{8 x}{25}$ - (i)

$⟹$ x+35 = 4y

$⟹$ x+35 = $\frac{32 x}{25}$ {From (i)}

$⟹$ x = 125

$∴$ y = 40

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One – fifth of a number is equal to 58th of another number. If 35 is added to the first number, the result is four times the second number. The second number is:

The correct option is B 40 Let the number be x and y. Then, x5 = 5y8 ⟹ y = 8x25 - (i) ⟹ x+35 = 4y ⟹ x+35 = 32x25 {From (i)} ⟹ x = 125 ∴ y = 40

One – fifth of a number is equal to ${\frac{5}{8}}^{t h}$ of another number. If 35 is added to the first number, the result is four times the second number. The second number is:

The correct option is B
40

Let the number be x and y. Then,

$\frac{x}{5}$ = $\frac{5 y}{8}$

$⟹$ y = $\frac{8 x}{25}$ - (i)

$⟹$ x+35 = 4y

$⟹$ x+35 = $\frac{32 x}{25}$ {From (i)}

$⟹$ x = 125

$∴$ y = 40