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Standard VII

Physics

Inter-Conversion of Temperature in Different Scales

One-fifth of ...

Question

One-fifth of the temperature (C) in centigrade of body increased by 12 $^{o}$ is equal to its temperature in Fahrenheit (F). Find C when F = 34 $^{o}$ .

100

degrees

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110

degrees

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120

degrees

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130

degrees

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Solution

The correct option is B $110$ degrees
From the given statement, we can write the formula as
$F = \frac{1}{5} C + 12$
Substituting $F = 34$ in the above formula, we get
$34 = \frac{1}{5} C + 12$

$C = 22 \times 5$ B

$C = 110$ degrees

So, option B is correct.

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Similar questions

Q. One-fifth of the temperature (C) in centigarde of body increased by 10

^{o}

is equal to its temperature in Fahrenheit (F). Find F when C = 20

^{o}

Q. On the centigrade scale, the temperature of a body increases by

30

degrees. The increase in temperature on the Fahrenheit scale is :

C = \frac{5}{9} (F - 32)

The equation above shows how a temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?
I. A temperature increase of

1

degree Fahrenheit is equivalent to a temperature increase of

\frac{5}{9}

degree Celsius.
II. A temperature increase of

1

degree Celsius is equivalent to a temperature increase of

1.8

degrees Fahrenheit.
III. A temperature increase of

\frac{5}{9}

degree Fahrenheit is equivalent to a temperature increase of

1

degree Celsius

Q. Sneha uses the relationship shown to change between temperatures in degrees Fahrenheit

(^{\circ} F)

and temperatures in degreesCelsius

(^{\circ} C)

Sasha thinks that

30^{\circ} C

ishigher than

82^{\circ} F

.Is she correct? Show how you worked out your answer.

Relationship used by Sneha:

5 f = 9 C + 160

where:

f

is the temperature in degrees Fahrenheit (

(^{\circ} F)

C is the temperature in degrees Celsius

(^{\circ} C)

Q. The function

t

which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by

t (C) = \frac{9 C}{5} + 32^{o}

Find :

(i)

t (0^{o})

(ii)

t (28^{o})

(iii)

t (- 10^{o})

(iv) The value of

C

when

t (C) = 212^{o} F

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One-fifth of the temperature (C) in centigrade of body increased by 12o is equal to its temperature in Fahrenheit (F). Find C when F = 34o.

The correct option is B 110 degreesFrom the given statement, we can write the formula asF=15C+12Substituting F=34 in the above formula, we get34=15C+12C=22×5BC=110 degreesSo, option B is correct.

One-fifth of the temperature (C) in centigrade of body increased by 12 $^{o}$ is equal to its temperature in Fahrenheit (F). Find C when F = 34 $^{o}$ .

The correct option is B $110$ degrees
From the given statement, we can write the formula as
$F = \frac{1}{5} C + 12$
Substituting $F = 34$ in the above formula, we get
$34 = \frac{1}{5} C + 12$

$C = 22 \times 5$ B

$C = 110$ degrees

So, option B is correct.