One gram mole of a gas at NTP occupies $22.4$ litres as volume. This fact was derived from:

Dalton's theory

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Avogadro's hypothesis

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Berzelius hypothesis

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law of gaseous volumes

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Solution

The correct option is C Avogadro's hypothesis
One gram mole of a gas at NTP requires 22.4 as volume. This fact was derived from Avogadro's hypothesis.
Taking STP to be 101.325 kPa and 273.15 K, we can find the volume of one mole of a gas.

Volume = $\frac{R T}{ρ}$ = $\frac{8.314 \times 273.15}{101.325} = 22.4 L$

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