One gram molecule of any gas at $N T P$ occupies $22.4 L$ . This fact was derived from:

Dalton's theory

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Avogardro's hypothesis

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Berzelius hypothesis

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Law of gaseous volume

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Solution

The correct option is B Avogardro's hypothesis
According to Avogadro's law, 1 mole of every gas occupies 22.4L at $N T P$ .
From ideal gas equation,
$P V = n R T$ . . . . . . .(1)
At $N T P$ ,
$T = 273 K$
$P = 1 a t m$
$n = 1$
$R = 0.0821 a t m L / K m o l$
from equation (1),
$V = \frac{n R T}{P}$
$V = \frac{1 \times 0.0821 \times 273}{1} = 22.4 L$
The correct option is B.

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