One gram of a radioactive element decays by -emission to 0-125 in 200 hours- How much will more time elapse until only 0-10 g of it is left-

K= 2.303 200 × log( 1 0.125 #160; ) =0.010 hr ^ 1 t= 2.303 0.010 log( 1 0.10 #160; ) t=230.3 hr ...

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Byju's Answer

Standard IX

Chemistry

Radioactivity

One gram of a...

Question

One gram of a radioactive element decays by $β$ -emission to $0.125$ in $200$ hours. How much will more time elapse until only $0.10 g$ of it is left?

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Solution

$K = \frac{2.303}{200} \times l o g (\frac{1}{0.125}) = 0.010 {h r}^{- 1}$
$t = \frac{2.303}{0.010} l o g (\frac{1}{0.10})$
$t = 230.3$ hr

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