one gram of hydrated copper sulphate solution gave on heating 0.6393g of anhydrous salt.calculate the number of molecules of water of crystallisation per molecule of the hydrated salt

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Solution

$W e i g h t o f h y d r a t e d c o p p e r s u l p h a t e s o l u t i o n = 1 g W e i g h t o f a n h y d r o u s s a l t = 0.6393 g W e i g h t o f w a t e r = 1 - 0.6393 = 0.3607 g M o l e s o f c o p p e r s u l p h a t e a n d w a t e r = \frac{0.6393}{159.5} a n d \frac{0.3607}{18} = 0.004008 a n d 0.02004 S i m p l e r a t i o = \frac{0.004008}{0.02004} a n d \frac{0.02004}{0.02004} = 0.2 a n d 1 T o m a k e i t a s w h o l e n u m b e r m u l t i p l y b y S o t h e n u m b e r o f C u S O_{4} a n d w a t e r = 1 a n d 5 T h u s t h e n u m b e r o f w a t e r m o l e c u l e s = 5$

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