One integer is chosen out of 1,2,3,...,100. What is the probability that it is neither divisible by 4 nor by 6.
A
0.59
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B
0.67
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C
0.41
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D
0.33
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Solution
The correct option is B0.67 From 1−100, Numbers which are divisible by 4=25 Numbers which are divisible by 6=16 Numbers which are divisible by 12=8 Numbers divisible by 4 or 6=25+16−8=33 Thus, numbers which are not divisible by 4 or 6=100−33=67 Required probability =67100=0.67 Hence, option B is correct.