One integer is chosen put of 1,2,3, ....... 100. What is the probability that it is neither divisible by 4 nor by 6?
A
0.59
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B
0.67
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C
0.41
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D
0.33
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Solution
The correct option is B0.67 We take numbers from 1 to 50 Numbers divisible by 4 = 25 Numbers divisible by 6 = 16 Numbers divisible by 12 = 8 Numbers divisible by 4 or 6 =25+16-8=33 Numbers not divisible by 4 or 6=100-33=67 So, required probability =67100=0.67