One junction of a certain thermoelectric couple is at a fixed temperature $T_{r}$ and the other junction is at temperature T. The thermo-electromotive force for this is expressed by $E = k (T - T_{r}) [T_{0} - \frac{1}{2} (T + T_{r})]$ . At temperature $T = \frac{1}{2} T_{0}$ , the thermoelectric power is :

\frac{1}{2} k T_{0}

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k T_{0}

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\frac{1}{2} k T_{0}^{2}

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\frac{1}{2} k {(T_{0} - T_{r})}^{2}

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Solution

The correct option is A $\frac{1}{2} k T_{0}$
We know that thermoelectric power
$S = \frac{d E}{d T}$
Given, $E = K (T - T_{r}) [T_{0} - \frac{1}{2} (T + T_{r})]$
By differentiating the above equation w.r.t. T and putting $T = \frac{1}{2} T_{0}$ , we get $S = \frac{1}{2} K T_{0}$

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Similar questions

T_{r}

E = K (T - T_{r}) [T_{0} - \frac{1}{2} (T + T_{r})]

T_{0} / 2

E = α t + \frac{1}{2} β t^{2}

0^{0}

t^{o} C

E = a t + b t^{2}

E = α T + \frac{1}{2} β T^{2}

0^{o} C

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