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Question

# One kg of air in a closed system undergoes an irreversible process from an initial state of p1=1 bar (absolute) and T1=27oC, to a final state of p2=3 bar (absolute) and T2=127oC. If the gas constant of air is287 J/kgK and the ratio of the specific heats γ=1.4, then the change in the specific entropy (in J/kgK) of the air in the process is

A
28.4
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B
172.0
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C
indeterminate, as the process is irreversible
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D
26.3
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Solution

## The correct option is D −26.3 P1=1bar,P2=3bar,T1=300K,T2=400 K, cp=γRγ−1=1.4×2870.4 =1005J/kgK ΔS=cplnT2T1−RlnP2P1 =1005ln400300−287ln31 −26.32J/kgK

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