One kg of ice at 0oC is mixed with 1kg of water at 10oC. The resulting temperature will be
A
between 0oC and 10oC
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B
0oC
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C
less than 0oC
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D
greater than 0oC
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Solution
The correct option is C0oC Solution:
Specific heat of water is 1 cal/g. There is totally 1kg, so it possesses 1000cal of energy. Now, since ice is already at 0oC, it needs latent heat to turn into water. This energy is provided by the water. Latent heat of ice is 80cal/g. So, for 1kg, it requires 8000cal. But water only possess 1000cal of energy. So, only certain mass of ice will get converted into water at 0oC, and the rest of the water at 10oC will cool down to 0oC also. But, since only 1000cal is available, part of the ice remains as ice. So, temperature in the end is 0oC.