One leg of a right angle triangle exceeds the other leg by 4 inches. Length of the hypotenuse is 20 inches. Find the length of the shorter leg of the triangle.

12 inches

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7 inches

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20 inches

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14 inches

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Solution

The correct option is A
12 inches

Let length of triangle legs x and x+4

Applying Pythagoras theorem,

$x^{2}$ + $(x + 4)^{2}$ = $(20)^{2}$

we get x = -16 and x = 12

Length can’t be negative.

Therefore, the length of a shorter side of the triangle is 12 inches.

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One leg of a right angle triangle exceeds the other leg by 4 inches. Length of the hypotenuse is 20 inches. Find the length of the shorter leg of the triangle.

The correct option is A 12 inches Let length of triangle legs x and x+4 Applying Pythagoras theorem, x2+(x+4)2=(20)2 we get x = -16 and x = 12 Length can’t be negative. Therefore, the length of a shorter side of the triangle is 12 inches.

The correct option is A
12 inches

Let length of triangle legs x and x+4

Applying Pythagoras theorem,

$x^{2}$ + $(x + 4)^{2}$ = $(20)^{2}$

we get x = -16 and x = 12

Length can’t be negative.

Therefore, the length of a shorter side of the triangle is 12 inches.