One leg of a right angled triangle exceeds the other leg by 4 inches. The hypotenuse is 20 inches. Find the length of the shorter leg of the triangle.
Let the length of the legs of the triangle be x and x+4 inches.
Applying Pythagoras' theorem,
Solving the quadratic equation,x2+16x−12x−192=0x(x+16)−12(x+16)=0(x+16)(x−12)=0∴x=−16 & 12
Length can't be negative, hence
The shortest side(leg) is 12 .