One liter of a gas weight $4 g$ at $300 K$ and $1$ atm. If the pressure is reduced to $0.75$ atm,the temperature at which one litre of the same gas weight $2 g$ is:

600 K

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900 K

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450 K

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800 K

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Solution

The correct option is C $450 K$
$P M = d R T \Rightarrow T = \frac{P M}{d R}$

Initially, $300 = \frac{1 \times M}{4 \times R} \Rightarrow \frac{M}{R} = 1200$

Now, $T = \frac{0.75 \times M}{2 \times R}$

$= \frac{3}{8} \times 1200 = 450 K$

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Q. One litre of a gas weighs

2 g

300 K

and

1 a t m

pressure. If the pressure is made

0.75 a t m

at which of the following temperatures will one litre of the same gas, weigh one gram?

The weight of one litre of a gas at 1atm. Pressure and 300K is 4g. At what temperature the weight of the gas is 4g when the pressure is made 0.5 atm and volume is 1 litre?

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One liter of a gas weight 4g at 300K and 1 atm. If the pressure is reduced to 0.75 atm,the temperature at which one litre of the same gas weight 2g is:

The correct option is C 450KPM=dRT⇒T=PMdRInitially, 300=1×M4×R⇒MR=1200Now, T=0.75×M2×R=38×1200=450K

One liter of a gas weight $4 g$ at $300 K$ and $1$ atm. If the pressure is reduced to $0.75$ atm,the temperature at which one litre of the same gas weight $2 g$ is:

The correct option is C $450 K$
$P M = d R T \Rightarrow T = \frac{P M}{d R}$

Initially, $300 = \frac{1 \times M}{4 \times R} \Rightarrow \frac{M}{R} = 1200$

Now, $T = \frac{0.75 \times M}{2 \times R}$

$= \frac{3}{8} \times 1200 = 450 K$