Question

One liter of gas is twice as heavy as one liter of methane under the same conditions. The gas is :

• A. ozone
• B. dioxygen
• C. carbon dioxide
• D. sulphur dioxide

Answer 1

The correct option is B dioxygen

Since, for same condition($P,V,T$),

$\rho \propto M$

hence,

$\frac{M_g}{M_{C{H}_4}}=\frac{{\rho }_g}{{\rho }_{C{H}_4}}=\frac{2{\rho }_{C{H}_4}}{{\rho }_{C{H}_4}}=2$

$\Rightarrow M_g=2\times M_{C{H}_4}=2\times 16=32$

Among the given alternatives the gas having a molecular mass of $32$ is $O_2$