Question

One liter of oxygen at NTP is allowed to react with three times of carbon monoxide at NTP. What will be the volume of each gas found after the reaction?

Answer 1

The desired equation is;
$\underset{2vol.}{2CO}+\underset{1vol.}{O_2}\to \underset{2vol.}{2C{O}_2}$
1 vol. of $O_2$ reacts with 2 vol. of $CO$
or 1 lime of $O_2$ reacts with 2 litre of $CO$
Thus, 1 litre of $CO$ remains unreacted.
1 vol. of $O_2$ produces $C{O}_2=2vol.$
Or 1 litre of $O_2$ will produce $C{O}_2=2litre$
Thus, gaseous mixture after the reaction consists Volume of $CO=1litre$
Volume of $C{O}_2=2litre$