Question

One litre of 1 molar $H_{2}S{O}_4$ solution has been diluted by 5 litre water, the normality of the solution is

• A. 0.2N
• B. 5N
• C. 10N
• D. 0.33N

Answer 1

The correct option is D 0.33N

$M_1{V}_1=M_2{V}_2$
$where{V}_1=1litre,M_1=1m$
$V_2=1+5=6litre,M_2=?$
thus,
$1\times 1=6\times M_2$
$M_2=\frac{1}{6}$ $[{}^{\prime }{n}^{\prime }factorof{H}_{2}S{O}_4=2]$
But normality='n' factor $\times$ molarity = 2 $\times$ $\frac{1}{6}=\frac{1}{3}$
$N=\frac{1}{3}$