One litre of a gas at STP weight 1.16 g it can possible be

C H_{4}

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O_{2}

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C_{2} H_{2}

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C O

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Solution

The correct option is C $C_{2} H_{2}$
$∵$ 1L of gas at S.T.P. weight 1.16g
$∴$ 22.4 L of gas at S.T.P. weight = $22.4 \times 1.16 = 25.984 \approx 26$
This molecular weight indicates that given compound is $C_{2} H_{2}$

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