One litre of a gas weighs $2$ g at $300$ K and $1$ atm pressure. If the pressure is made $0.75$ atm, at which temperature will one litre of the same gas weighs $1$ g?

600

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800

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900

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450

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Solution

The correct option is D $450$ K
$As P V = \frac{m}{M} R T \Rightarrow M = \frac{m R T}{P V} \frac{m_{1} R T_{1}}{P_{1} V_{1}} = \frac{m_{2} R T_{2}}{P_{2} V_{2}} [for the same gas] \Rightarrow \frac{(2) (R) (300)}{1} = \frac{(1) (R) (T)}{0.75} T = (600) (0.75) = 450 K$

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One litre of a gas weights 2g at 300 K and 1 atm. pressure. If the pressure is made 0.75 atm, at which temperature will one litre of the same gas weigh 1g

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Q. One litre of a gas weighs 2 g at 300 K and 1 atm. If the pressure is made 0.75 atm, at what temperature will one litre of the same gas weigh one gram?

Q. One litre of a gas weighs

2 g

300 K

and

1 a t m

pressure. If the pressure is made

0.75 a t m

at which of the following temperatures will one litre of the same gas, weigh one gram?

Q. One litre of gas of mass,

2 g

300 K

and

1

atm pressure, the pressure is made

0.75

atm, at which of the following temperatures will one litre of the same gas have mass of one gram.

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One litre of a gas weighs 2g at 300K and 1 atm pressure. If the pressure is made 0.75 atm, at which temperature will one litre of the same gas weighs 1g?

The correct option is D 450KAs PV=mMRT⇒M=mRTPVm1RT1P1V1=m2RT2P2V2 [for the same gas]⇒(2)(R)(300)1=(1)(R)(T)0.75T=(600)(0.75)=450K

One litre of a gas weighs $2$ g at $300$ K and $1$ atm pressure. If the pressure is made $0.75$ atm, at which temperature will one litre of the same gas weighs $1$ g?

The correct option is D $450$ K
$As P V = \frac{m}{M} R T \Rightarrow M = \frac{m R T}{P V} \frac{m_{1} R T_{1}}{P_{1} V_{1}} = \frac{m_{2} R T_{2}}{P_{2} V_{2}} [for the same gas] \Rightarrow \frac{(2) (R) (300)}{1} = \frac{(1) (R) (T)}{0.75} T = (600) (0.75) = 450 K$