One litre of a gas weighs 2g at $300 K$ and $1$ atm. If the pressure is made $0.75$ atm at what temperature will one litre of the same gas weigh one gram?

450 K

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800 K

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600 K

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900 K

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Solution

The correct option is C $450 K$
Considering, $n_{1}$ = 2 g ; $n_{2}$ = 1g
We know,
$n = \frac{g i v e n m a s s}{m o l a r m a s s} = \frac{w}{M}$

Now,
$\frac{P_{1}}{n_{1} T_{1}} = \frac{P_{2}}{n_{2} T_{2}} ⟹ \frac{1 a t m}{\frac{2 g}{M} \times 300 K} = \frac{0.75 a t m}{\frac{1 g}{M} \times T_{2}} ⟹ T_{2} = 450 K$

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One litre of a gas weighs 2g at 300K and 1 atm. If the pressure is made 0.75 atm at what temperature will one litre of the same gas weigh one gram?

The correct option is C 450KConsidering, n1 = 2 g ; n2 = 1gWe know,n=given massmolar mass=wMNow,P1n1T1=P2n2T2⟹1atm2gM×300K=0.75atm1gM×T2⟹T2=450K

One litre of a gas weighs 2g at $300 K$ and $1$ atm. If the pressure is made $0.75$ atm at what temperature will one litre of the same gas weigh one gram?