One litre of a gas weights 2g at 300 K and 1 atm. pressure. If the pressure is made 0.75 atm, at which temperature will one litre of the same gas weigh 1g

600K

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800K

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900K

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450K

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Solution

The correct option is D
450K

PV = nRT

$\frac{P_{1}}{P_{2}}$ = $\frac{V_{1}}{V_{2}}$ $\frac{T_{1}}{T_{2}}$

$\frac{1}{0.75}$ = $\frac{2}{1}$ $\times$ $\frac{300}{T_{2}}$

$T_{2}$ = 600 $\times 0.75$ = 6 $\times$ 75 = 450 k

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One litre of a gas weights 2g at 300 K and 1 atm. pressure. If the pressure is made 0.75 atm, at which temperature will one litre of the same gas weigh 1g

The correct option is D 450K PV = nRT P1P2 = V1V2 T1T2 10.75 = 21 × 300T2 T2 = 600 ×0.75 = 6 × 75 = 450 k

The correct option is D
450K

PV = nRT

$\frac{P_{1}}{P_{2}}$ = $\frac{V_{1}}{V_{2}}$ $\frac{T_{1}}{T_{2}}$

$\frac{1}{0.75}$ = $\frac{2}{1}$ $\times$ $\frac{300}{T_{2}}$

$T_{2}$ = 600 $\times 0.75$ = 6 $\times$ 75 = 450 k