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Basic Buffer Action

One litre of ...

Question

One litre of an aqueous solution contains $0.15$ mole of $C H_{3} C O O H (p K_{a} = 4.8)$ and $0.15$ mole of $C H_{3} C O O N a$ . After the addition of $0.05$ mole of solid $N a O H$ to this solution, the $p H$ will be:

A

4.5

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B

4.8

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C

5.1

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D

5.4

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Solution

The correct option is C $5.1$
$C H_{3} C O O H (p K_{a} = 4.8)$
$p H = p K_{a} + log \frac{[Conjugate Base]}{[A c i d]}$
After adding NaOH, it will react with acid and salt forms so now
$p H = p K_{a} + log \frac{[Conjugate Base]}{[A c i d]} = 4.8 + l o g (0.15 + 0.05) / (0.15 - 0.05) = 4.8 + l o g (0.20 / 0.10) = 5.1$

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