One litre of an unknown gas weights 1.25 gm at N.T.P. Which of the following gas pertains to the above data?

C O_{2}

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N O_{2}

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N_{2}

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O_{2}

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Solution

The correct option is C $N_{2}$
At NTP, 22.4 litres of any gas is equal to 1 mole.

Hence 1 litre can make $\frac{1}{22.4}$ moles.

$n = \frac{m}{M}$

where,
m = Given mass
M = Molar mass
n = Number of moles

Therefore, $\frac{m}{M} = \frac{1}{22.4}$

$M = 1.25 \times 22.4$

$= 28 g m$

The molar mass of $N_{2}$ is $28$ .

Hence, option C is correct.

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Similar questions

Q. One litre of an unknown gas weighs

1.25

g at N.T.P. Which of the following gas pertains to the given data.

Q. One litre of an unknown gas weighs

1.25 g

S T P

. Which of the following gas pertains to the above data?

Q. Gases

H_{2} H e O_{2} N_{2}

Critical temperature(K) 33.2 5.3 154.3 126

From the above data what whould be the order of liquefaction of these gases?
Start writing the order from the gas liquefying first.

Gases posses charcteristic critical temperature which depends upo the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.

$\begin{matrix} G a s e s & H_{2} & H e & O_{2} & N_{2} C r i t i c a l t e m p e r a t u r e i n K e l v i n & 33.2 & 5.3 & 154.3 & 126 \end{matrix}$

From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first

(a) $H_{2}, H e, O_{2}, N_{2}$ (b) $H e, O_{2}, H_{2}, N_{2}$

Q. For the gas phase reaction,

2 N O ⇌ N_{2} + O_{2}; Δ H = - 43.5 k c a l

Which of the following is/are true of

N_{2} + O_{2} ⇌ 2 N O ?

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One litre of an unknown gas weights 1.25 gm at N.T.P. Which of the following gas pertains to the above data?

The correct option is C N2At NTP, 22.4 litres of any gas is equal to 1 mole.Hence 1 litre can make 122.4 moles.n=mMwhere, m = Given massM = Molar massn = Number of molesTherefore, mM=122.4M=1.25×22.4 =28 gmThe molar mass of N2 is 28.Hence, option C is correct.