One litre of $C O_{2}$ is passed through red hot coke. The volume becomes 1.4 litres at the same temperature and pressure.The composition of products is:

0.6 litre of

C O_{2}

and 0.8 litre of

C O

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0.7 litre of

C O_{2}

and 0.7 litre of

C O

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0.6 litre of

C O_{2}

and 0.7 litre of

C O

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0.4 litre of

C O_{2}

and 1.0 litre of

C O

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Solution

The correct option is A 0.6 litre of $C O_{2}$ and 0.8 litre of $C O$
$C O_{2} + C ⟶ 2 C O$

Let $x L$ be the volume of $C O_{2}$ combining with coke forming $2 x L$ of $C O$

$∴$ Volume of $C O_{2}$ left= $1 - x$

Total volume= $1.4 L$

$\Rightarrow 1 - x + 2 x = 1.4$

$\Rightarrow x = 0.4$

Volume of $C O = 2 \times 0.4 = 0.8 L$

$\Rightarrow C O_{2} = 1 - 0.4 = 0.6 L$

$∴$ Composition of products, $0.6 L$ of $C O_{2}$ & $0.8 L$ of $C O$

Hence, the correct option is $A$

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