Question

One litre of helium under a pressure of 2 atm and at 27${}^0$C is heated until its pressure and volume are doubled. The final temperature attained by the gas is

• A. 927 K
• B. 927${}^0$C
• C. 1200${}^0$C
• D. None

Answer 1

Answer: (B)

927${}^0$C

from ideal gas equation, PV = nRT
So, $T=\frac{PV}{nR}$
Since, n is constant, and R is also constant, we can say that T is directly proportional to the product of P and V
$T\alpha PV$
Since both volume and pressure are doubled, absolute temperature of the gas will become 4 times
Initial temperature = 27${}^{\circ }$C = 300K
So, final temperature = 4 x 300K = 1200 K = 927 ${}^{\circ }$ C
So, B is the correct answer.