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Stoichiometric Calculations

One litre of ...

Question

One litre of N/2 HCl solution is heated in a beaker. It was observed that when the volume of the solution was reduced to 600 mL, 3.25 g of HCl in lost, calculate the normality of the new solution.

1.7

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0.685

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0.342

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0.171

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Solution

The correct option is B 0.685
The original of $0.5 N H C l$ solution of $1 l i t r e$ had $18.225 g m$ of $H C l$

Initially $18.225 g m$ of $H C l$ was dissolved in 1 liter of silution

After heating , mass of HCl dissolved in the reduced $600 m L$ of solution was found to be $(18.225 - 3.25) g m = 14.975 g m$

Hence

$N o r m a l i t y o f n e w s o l u t i o n = \frac{E q u i v a l e n t w e i g h t o f H C l m a s s}{V o l u m e o f s o l u t i o n i n l i t r e}$

$N = \frac{\frac{14.497}{E q u i v a l e n t w e i g h t o f H C l}}{\frac{600 m L}{1000 m L p e r l i t r e}}$

$N = \frac{\frac{14.497}{36.45}}{0.6 l i t r e}$

$N = \frac{0.3977 M e q}{0.6 l i t r e}$

$N = 0.685$

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