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Question

One litre of saturated solution of CaCO3 is evaporated to dryness due to which 7.0 mg of residue is left. The solubility product for CaCO3 is:

A
4.9×105
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B
4.9×109
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C
4.9×109
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D
4.9×107
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Solution

The correct option is C 4.9×109
Moles of CaCO3 in the residue =residue massmolar mass of calcium carbonate=7×103100=7×105
Concentration of CaCO3 in 1 litre solution =7×105
CaCO3(s)Ca2(aq)+CO23(aq) 1 0 0 1s s s

Ksp=[Ca2+][CO23]
=7×105×7×105=4.9×109

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