One litre of saturated solution of CaCO3 is evaporated to dryness due to which 7.0 mg of residue is left. The solubility product for CaCO3 is:
A
4.9×10−5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4.9×109
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4.9×10−9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
4.9×10−7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C4.9×10−9 Moles of CaCO3 in the residue =residue massmolar mass of calcium carbonate=7×10−3100=7×10−5 Concentration of CaCO3 in 1 litre solution =7×10−5 CaCO3(s)⇌Ca2(aq)+CO2−3(aq)1001−sss