Question

One litre of water contains ${10}^{-7}$ mole of $H^{+}$ ions. Degree of ionisation of water is:

• A. $1.8\times {10}^{-7}\%$
• B. $0.8\times {10}^{-9}\%$
• C. $3.6\times {10}^{-9}\%$
• D. $3.6\times {10}^{-7}\%$

Answer 1

The correct option is A $1.8\times {10}^{-7}\%$

$1$ litre of water contains $1000/18$ mole.

So degree of ionization $=\frac{{10}^{-7}\times 18}{1000}=1.8\times {10}^{-7}\%$
Option A is correct.