One mapping (function) is selected at random from all the mappings of the set A={1,2,3,.....,n} into itself. The probability that the mapping selected is one to one is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C

Required probability = $\frac{(n - 1)!}{n^{n - 1}}$

Suggest Corrections

Similar questions

Q. One mapping is selected at random from all mappings of the set A = {1, 2, 3, ..., n} into itself. The probability that the mapping selected is one to one is

(a)

\frac{1}{n^{n}}

(b)

\frac{1}{n!}

(c)

\frac{(n - 1)!}{n^{n - 1}}

(d) None of these

One mapping is selected at random from all the mapping of the set A = {1, 2, 3, ......, n} into itself. The probability that the mapping selected is one to one is

Q. A mapping is selected at random from the set of all the mappings of the set A = {1, 2, …….., n} into itself. The probability that the mapping selected is an injection is:

Q. One mapping (function) is selected at random from all the mappings of the set

A = {1, 2, 3, . . ., n}

into itself. The probability that the mapping selected is one-one, is

Join BYJU'S Learning Program

One mapping (function) is selected at random from all the mappings of the set A={1,2,3,.....,n} into itself. The probability that the mapping selected is one to one is

The correct option is C Required probability = (n−1)!nn−1

The correct option is C

Required probability = $\frac{(n - 1)!}{n^{n - 1}}$