Question

One mole each of $H_{3}P{O}_2,H_{3}P{O}_3$ and $H_{3}P{O}_4$ will neutralize '$x$' mol of $NaOH,\text{'}y\text{' mol of Ca}{\left(OH\right)}_2$ and $\text{'}z\text{' mol of Al}{\left(OH\right)}_3$ (assuming all to be strong electrolytes) respectively. $x,y$ and $z$ are in the ratio:

• A. $3:1.5:1$
• B. $1:2:3$
• C. $3:2:1$
• D. $1:1:1$

Answer 1

The correct option is D $1:1:1$


1 mole of $H_{3}P{O}_2$ will neutralize 1 mole of $NaOH$

1 mole of $H_{3}P{O}_3$ will neutralize 1 mole of $Ca(OH{)}_2$

1 mole of $H_{3}P{O}_4$ will neutralize 1 mole of $Al(OH{)}_3$

$\therefore$ The reatio of $x:y:z$ is $1:1:1$