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Question

One mole gas expands with temp. as V=KT2/3.What is the work done when temp.change by 30c?

A
10R
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B
20R
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C
30R
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D
40R
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Solution

The correct option is B 20R
Given,
dT=300
V=KT2/3. . . . . . . .(1)
n=1mole

dV=2K3T1/3dT. . . . . . .(2)
Work done, W=PdV

W=nRTVdV (PV=nRT)

Substitute equation (1), and equation (2) in the above equation, we get

W=2R3dT

W=2R3×30=20R
The correct option is B.

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