One mole of 1,2-dibromopropane on treatment with $X$ moles of $N a N H_{2}$ followed by treatment with ethyl bromide gave a 2-pentyne. The value of $X$ is:

one

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two

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three

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four

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Solution

The correct option is B three
$C H_{3} C H (B r) C H_{2} (B r) 2 N a N H_{2} - ---- \to C H_{3} - C \equiv C H N a N H_{2} - ---- \to {C H_{3} - C \equiv C}^{-} {N a}^{+} C_{2} H_{5} B r - ---- \to C H_{3} C \equiv C C H_{2} C H_{3}$
Hence, $X = 3$ .

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