One mole of a gas expands by $3 L$ against a constant pressure of $3$ atmosphere. Calculate the work done in calories.

Open in App

Solution

The work done $(W)$ when the gas expands at constant pressure $P (= 3 a t m)$ from volume $V_{1}$ to $V_{2}$ is given by
$W = - \int_{V_{1}}^{V_{2}} P d v$
$= - P \int_{V_{1}}^{V_{2}} d v$
$= - P (V_{2} - V_{1} = - P Δ V$
where, negative sign indicates work done by the system.
Here $△ V = 3 L$
We know, $1 J o u l e s = 0.2390 c a l o r i e s$
Thus, $W = - 911.925 \times 0.2390 C a l = 217.95$ calories

Suggest Corrections

Similar questions

3 L

3

3 L

3

0.5

A gas expands by $0.5$ L against a constant pressure of $1$ atm. The work done in calories is:

A gas expands by $0.5$ liter against a constant pressure of one atmosphere. then the work done in Joules is:

Join BYJU'S Learning Program