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Question

One mole of a gas is expanded from (1 L, 10 atm,300K) to (4 L, 5 atm,600K) against a constant external pressure of 1 atm. The heat capacity of gas is 50 J/K.Then the enthalpy change during the process is (1 L atm 100 J)

A
H=15 kJ
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B
H=15.7 kJ
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C
H=14.4 kJ
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D
H=14.7 kJ
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Solution

The correct option is B H=15.7 kJ
State 1 State 2
(1 L, 10 atm, 300K) (4 L, 5 atm, 600 K)
Heat given,q=nCT
where C is the heat capacity and T is the change in Temperature
Therefore,
q = 50 (600 - 300) = 15000 J
And,
W=Pext(V2V1)=1(41)=3 L atm=300 J
E=q+W=15000300=14700 J
H=E+P2V2P1V1=14700 J+(2010)×100 J=15.7 kJ

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