One mole of a gas is expanded from 1L,10 atm,300K to 4 L,5atm,600K against a constant external pressure of 1atm. The heat capacity of gas is 50J/K.Then the internal energy change during the process is: (1L atm≃100J).
A
△U=14.7kJ
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B
△U=−14.7kJ
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C
△U=−28.7kJ
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D
△H=−20.6kJ
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Solution
The correct option is A△U=14.7kJ State 1State 2(1L,10atm,300K)(4L,5atm,600K)
Heat given, q=nC△T
where, C is the heat capacity and △T is the change in Temperature
Therefore, q=50(600−300)=15000J
And, W=−Pext(V2−V1)=−1(4−1)=−3 L atm=−300J △U=q+W=15000−300=14700J