Question

One mole of a gas is heated at constant pressure to raise its temperature by $1{}^{\circ }C.$ The work done in joules is:

• A. $-4.32J$
• B. $-8.31J$
• C. $-16.62J$
• D. Unpredictable

Answer 1

The correct option is B $-8.31J$

We know,
$w=-P\Delta V=-nR△T$

$\therefore -1\times 8.314\times 1=-P(\frac{nR{T}_2}{P}-\frac{nR{T}_1}{P})=-8.314J$