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Question
One mole of a gas is heated at constant pressure to raise its temperature by 1∘C. The work done is
One mole of a gas is heated at constant pressure to raise its temperature by 1∘C. The work done is
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Solution
The correct option is B -8.314 J
The work done can be given by:
w = −PΔV
w = −P(V2 − V1) = −P(nRT2P1 − nRT1P1)
P1 = P
∴ w = −nR(T2 − T1)
∴ w = −1 × 8.314 × 1
∴ w = −8.314
-8.314 J
The work done can be given by:
w = −PΔV
w = −P(V2 − V1) = −P(nRT2P1 − nRT1P1)
P1 = P
∴ w = −nR(T2 − T1)
∴ w = −1 × 8.314 × 1
∴ w = −8.314
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