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Question

One mole of a ideal gas expands obeying the relation as shown in the P/V diagram. The maximum temperature in this process is equal to

A
P0V0R
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B
3P0V0R
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C
9P0V08R
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D
None
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Solution

The correct option is C 9P0V08R
From the graph shown the equation of line is
PP0=⎜ ⎜ ⎜P02P02V0V0⎟ ⎟ ⎟(VV0)
PP0=P02V0(VV0)
P=P0V2V0+3P02
Now we know PV=nRT
(32P0P0V2V0)V=nRT
For maximum temperature
dTdV=032P0P0VV0=0
V=32V0
Tmax=(32P0P02V0.32V0)32V0.1nR
=34P0.32V0.1R=9P0V08R

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