Question

One mole of a monoatomic gas $(\gamma =1.66)$ is mixed with $2mol$ of a diatomic gas $(\gamma =1.4)$. For the value of $\gamma$ would be?

• A. $1.36$
• B. $1.46$
• C. $1.53$
• D. $1.54$

Answer 1

The correct option is B $1.46$

$n_1=1;n_2=2$

${\gamma }_1=1.66;{\gamma }_2=1.4$

Using formula,

$\frac{n_1+n_2}{{\gamma }_{mix}-1}=\frac{n_1}{{\gamma }_1-1}+\frac{n_2}{{\gamma }_2-1}$

$\frac{3}{{\gamma }_{mix}-1}=\frac{0.1}{0.66}+\frac{2}{0.4}$

$\frac{3}{{\gamma }_{mix}-1}=1.52+5$

${\gamma }_{mix}=\frac{3}{6.52}+1=1.46$