Question

One mole of a monoatomic ideal gas is mixed with one mole of a diatomic ideal gas. The molar specific heat of the mixture at constant volume is ________ in calories.

• A. 5
• B. 4
• C. 6
• D. 8

Answer 1

Answer: (B)

4

Given :One mole of a monoatomic ideal gas is mixed with one mole of a diatomic ideal gas. The molar specific heat of the mixture at constant volume is ________ in calories.

Solution :

The Volume of $\gamma$ of the mixture is given by

$\frac{n_1+n_2}{\gamma -1}$=$\frac{n_1}{{\gamma }_1-1}$+$\frac{n_2}{{\gamma }_2-1}$

$\frac{1+1}{\gamma -1}$=$\frac{1}{\frac{5}{3}-1}$+$\frac{1}{\frac{3}{2}-1}$

Solving we get the $\gamma =1.5$

We also know Specific heat $C_v=\frac{R}{\gamma -1}$

Substituting value of $\gamma$ we get $C_v=2R$

We need ans in calories and value of R in calories is 2

So $C_v=4$

The Correct Opt=B