One mole of a monoatomic real gas satisfies the equation p(V−b)=RT where, b is a constant. The correct relationship between interatomic potential V(r) and interatomic distance r for the gas is given by:
A
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B
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C
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D
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Solution
The correct option is C Given, p(V−b)=RT ⇒PV−Pb=RT⇒PVRT=PbRT+1
We know that, PVRT=ZZ=PbRT+1
Hence, Z>1 at all pressures.
This means that the repulsive forces will be dominant when the interatomic distance is small. Thus, the interatomic potential is never negative but becomes positive at small interatomic distances.
Hence, graph (c) is correct.