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Arrhenius Acid

One mole of a...

Question

One mole of ammonia was completely absorbed in one litre solution each of (a) $1 M$ $H C l$ , (b) $1 M$ $C H_{3} C O O H$ and (c) $1 M$ $H_{2} S O_{4}$ at $298 K$ .
The decreasing order for the pH of the resulting solutions is :
(Given $K_{b} (N H_{3}) = 4.74$ )

a > b > c

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c > b > a

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b > c > a

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b > a > c

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Solution

The correct option is B $b > a > c$
As the acidic character increases $p H$ decreases. Therefore pH will be in the order $b > a > c$

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Similar questions

1 M H C l

1 M C H_{3} C O O H

1 M H_{2} S O_{4}

298

p H

K_{b} (N H_{3}) = 4.74

A + B ⇌ C + D

C

D

0.8

K_{c}

A

B

1 M

H_{2} (g)

A^{n +}

Assume 100% ionisation in the following equimolal aqueous solution :

(a) 1m CaCl₂(b) 1m sucrose (c) 1m AlCl₃(d) 1m KCl

Arrange them in the increasing order of osmotic pressure:

\begin{matrix} E l e c t r o l y t e b e t w e e n i n e r t e l e c t r o d e s & C o n s e q u e n c e s o f e l e c t r o l y s i s (a) & K_{2} S O_{4} a q & (p) & L i b e r a t i o n o f O_{2} a t a n o d e (b) & C u S O_{4} a q (1 M) & (q) & L i b e r a t i o n o f H_{2} o f c a t h o d e (c) & N a C l_{a q} (1 M) & (r) & p H o f r e s u l t a n t s o l u t i o n d e c r e a s e s (b) & D i l . H_{2} S O_{4} (a c i d u l a t e d w a t e r) (n o r m a l c u r r e n t d e n s i t y) & (s) & p H o f r e s u l t a n t s o l u t i o n i n c r e a s e s (t) & C o n c e n t r a t i o n o f o r i g i n a l e l e c t r o l y t i c S o l u t i o n i n c r e a s e s \end{matrix}

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