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Question

One mole of an ideal diatomic gas is taken through the cycle as shown in the figure.
12 : Isochoric process
23 : Straight line on P-V diagram
31 : Isobaric process
The average molecular speed of the gas in the states 1,2 and 3 are in the ratio


A
1:2:2
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B
1:2:2
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C
1:1:1
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D
1:2:4
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Solution

The correct option is A 1:2:2
Applying the ideal gas equation,
At (1)
PoVo=(1)RT1T1=P0V0R=x(say)
At (2)
(4P0)(V0)=(1)RT2T2=4P0V0R=4x
At (3)
P0(4V0)=(1)RT3T3=4P0V0R=4x
We have for the molecules of the gas, Vav=8RTπMVavT

V1xV24xV34x

V1:V2:V3=1:2:2

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